The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm.

What is the approximate difference between m∠C and m∠A?

34.8°
44.8°
46.3°
47.9°

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HomertheGenius HomertheGenius · Answer 1 · 2017-02-09T17:48:28+01:00

cos ( ∠C ) = 5/13 = 0.38462
m ∠C = cos^(-1) 0.38642 = 67.4°
m ∠A = 90° - 67.4° = 22.6°
m ∠C - m ∠A = 67.4° - 22.6° = 44.8°
Answer:
B ) 44.8°

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vintechnology vintechnology · Answer 2 · 2022-02-14T13:58:37+01:00

The approximate difference between m∠C and m∠A is 44.8°

A right angle triangle has one of its angles as 90 degrees. The other two angles are complementary. Therefore,

Hypotenuse = AC = 13 cm

BC = 5 cm

Using trigonometric ratio, let's find the angle C.

Therefore,

cos C = adjacent / hypotenuse

cos C = 5 / 13

C = cos⁻¹ 0.38461538461

∠C = 67.4183269374°

∠A = 90 - 67.42 = 22.58°

Approximate difference = 67.42 - 22.58 = 44.8°

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