evaluate a = log(0.1) and b = ln(e^3)

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02-05-2018
Mathematics

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evaluate a = log(0.1) and b = ln(e^3)

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gmany gmany · Answer 1 · 2018-05-02T21:59:29+02:00

gmany gmany

02-05-2018

[tex]log0.1=log\dfrac{1}{10}=log10^{-1}=-log10=-1\to a=-1\\\\lne^3=3lne=3\to b=3\\\\Used:\\\\a^{-1}=\dfrac{1}{a}\\\ loga^b=b\cdot loga\\\\log_aa=1[/tex]

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